[SAC-HELP] Instrument responce files
shekar
m_shekar2k2 at rediffmail.com
Tue Nov 26 22:03:22 PST 2013
Hai all
Any body has the instrument response file(PZ file) for the following combination
1. Taurus digitizer+ Trillium 240 seismometer(240 sec, 1500v/m/s)
2. Reftek 72A+ CMG 40T(30 sec, 800 v/m/s)
Thank you very much.
shekar
On Tue, 26 Nov 2013 15:21:35 +0530 wrote
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Today's Topics:
1. Re: Insert hedder (Milton Plasencia)
----------------------------------------------------------------------
Message: 1
Date: Tue, 26 Nov 2013 06:45:34 -0300
From: Milton Plasencia
Subject: Re: [SAC-HELP] Insert hedder
To: shekar
Cc: sac-help at iris.washington.edu
Message-ID:
Content-Type: text/plain; charset="us-ascii"
Hi,
Use
> ch O GMT 2009 318 13 03 34 300
where 318 is the Julian day corresponding to month 11 and day 14.
HTH,
Milton P. Plasencia Linares
mpplasencia at gmail.com
On Nov 26, 2013, at 6:34 AM, shekar wrote:
> Dear all,
>
> I have a SAC file converted from SEISAN.
>
> How to insert the origin time(2009-11-14-13:03:34.300) of the event in sac header?
>
> Thanks in advance
>
> Shekar
>
>
> On Mon, 18 Nov 2013 22:14:49 +0530 wrote
> >Send sac-help mailing list submissions to
>
> sac-help at iris.washington.edu
>
>
>
> To subscribe or unsubscribe via the World Wide Web, visit
>
> http://www.iris.washington.edu/mailman/listinfo/sac-help
>
> or, via email, send a message with subject or body 'help' to
>
> sac-help-request at iris.washington.edu
>
>
>
> You can reach the person managing the list at
>
> sac-help-owner at iris.washington.edu
>
>
>
> When replying, please edit your Subject line so it is more specific
>
> than "Re: Contents of sac-help digest..."
>
>
>
>
>
> Today's Topics:
>
>
>
> 1. Re: sort and plot commands don't play (George Helffrich)
>
> 2. Remove Response Instrument (amik Amik)
>
> 3. Re: Remove Response Instrument (Arthur Snoke)
>
> 4. Re: Remove Response Instrument (Milton P. Plasencia Linares)
>
> 5. Calculation of AZ and BAZ in SAC (Fiona Darbyshire)
>
> 6. Re: Calculation of AZ and BAZ in SAC (Brian Savage)
>
>
>
>
>
> ----------------------------------------------------------------------
>
>
>
> Message: 1
>
> Date: Wed, 13 Nov 2013 09:03:30 +0000
>
> From: George Helffrich
>
> Subject: Re: [SAC-HELP] sort and plot commands don't play
>
> To: Frederik Tilmann
>
> Cc: sac-help at iris.washington.edu
>
> Message-ID:
>
> Content-Type: text/plain; charset=us-ascii
>
>
>
> Dear All -
>
>
>
> Plotting the traces in a record section in SSS displays traces in increasing distance order.
>
>
>
> On 13 Nov 2013, at 08:49, Frederik Tilmann wrote:
>
>
>
> > I have a problem in that the plot commands (p1,ppk) do not show the files in the same order as they are listed in memory after a sort.
>
> >
>
> > What I am trying to do is to display a north- to south record section of noise correlation functions with respect to a target station. The coordinates of both stations are place in evla and stla, but it is not well defined in which variable a given station ends up in (evla, or stla).
>
> >
>
> > So to plot all the functions relative to J10S I use
>
> >
>
> > r sumtraces-nonorm-0.03-0.10/*ZWZW*J10?J[0-9][0-9]*_sum.sac sumtraces-nonorm-0.03-0.10/*ZWZW*J[0-9][0-9]?J10?*_sum.sac
>
> > sort evla ascend stla ascend
>
> > lh evla stla
>
> >
>
> > Everything looks good, stations are in the right order in the lh list.
>
> >
>
> > But if I then do
>
> > p1
>
> > or ppk
>
> > they come out in the wrong order, plotting the J03-J10 after J10-J11 (correct would have been J09-J10 as in the lh listing). I attach a screenshot demonstrating this effect.
>
> > I tried
>
> > sort commit evla ascend stla ascend
>
> > but this this did not make a difference.
>
> >
>
> > This is on 101.5c
>
> > SEISMIC ANALYSIS CODE [02/01/2012 (Version 101.5c)]
>
> >
>
> >
>
> > Any ideas would be appreciated
>
> >
>
> > Regards
>
> > Frederik
>
> >
>
> >
>
> >
>
> >
>
> > Output of lh command
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J10BJ23B..HHZHHZ_sum.sac - 1
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.253600e+01
>
> > stla = 5.481430e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J10BJ22B..HHZHHZ_sum.sac - 2
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.270155e+01
>
> > stla = 5.481430e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J10BJ21B..HHZHHZ_sum.sac - 3
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.287174e+01
>
> > stla = 5.481430e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J10BJ20B..HHZHHZ_sum.sac - 4
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.305374e+01
>
> > stla = 5.481430e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J10BJ19B..HHZHHZ_sum.sac - 5
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.320426e+01
>
> > stla = 5.481430e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J10BJ18B..HHZHHZ_sum.sac - 6
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.339244e+01
>
> > stla = 5.481430e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J10BJ17B..HHZHHZ_sum.sac - 7
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.355617e+01
>
> > stla = 5.481430e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J10BJ25B..HHZHHZ_sum.sac - 8
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.366659e+01
>
> > stla = 5.481430e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J10BJ15B..HHZHHZ_sum.sac - 9
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.390106e+01
>
> > stla = 5.481430e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J10BJ14S..HHZHHZ_sum.sac - 10
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.411258e+01
>
> > Waiting
>
> >
>
> > stla = 5.481430e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J10BJ13B..HHZHHZ_sum.sac - 11
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.427260e+01
>
> > stla = 5.481430e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J10BJ12B..HHZHHZ_sum.sac - 12
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.444247e+01
>
> > stla = 5.481430e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J10BJ11S..HHZHHZ_sum.sac - 13
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.460217e+01
>
> > stla = 5.481430e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J09BJ10B..HHZHHZ_sum.sac - 14
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.481430e+01
>
> > stla = 5.640510e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J08SJ10B..HHZHHZ_sum.sac - 15
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.481430e+01
>
> > stla = 5.617126e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J07BJ10B..HHZHHZ_sum.sac - 16
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.481430e+01
>
> > stla = 5.603592e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J04BJ10B..HHZHHZ_sum.sac - 17
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.481430e+01
>
> > stla = 5.577234e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J03EJ10B..HHZHHZ_sum.sac - 18
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.481430e+01
>
> > stla = 5.530829e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J02SJ10B..HHZHHZ_sum.sac - 19
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.481430e+01
>
> > stla = 5.512811e+01
>
> >
>
> > FILE: sumtraces-nonorm-0.03-0.10/mat__ZWZW.J01EJ10B..HHZHHZ_sum.sac - 20
>
> > -------------------------------------------------------------------
>
> >
>
> > evla = 5.481430e+01
>
> > Waiting
>
> >
>
> > stla = 5.497167e+01
>
> > SAC>
>
> > _______________________________________________
>
> > sac-help mailing list
>
> > sac-help at iris.washington.edu
>
> > http://www.iris.washington.edu/mailman/listinfo/sac-help
>
>
>
>
>
>
>
> George Helffrich
>
> george.helffrich at bris.ac.uk
>
>
>
>
>
>
>
>
>
> ------------------------------
>
>
>
> Message: 2
>
> Date: Sun, 17 Nov 2013 16:07:33 +0800 (SGT)
>
> From: amik Amik
>
> Subject: [SAC-HELP] Remove Response Instrument
>
> To: "sac-help at iris.washington.edu"
>
> Message-ID:
>
>
>
> Content-Type: text/plain; charset="iso-8859-1"
>
>
>
> I am working on a local magnitude research. I want to remove response instrument
>
> from the data and simulate the response of Wood Anderson seismograph. What should I do?
>
> I have a few questions :
>
> 1. Which one the true procedure and command in SAC :
>
> ?? a) SAC> trans from evalresp to none
>
> ?? ? ?and then
>
> ?? ? ?SAC> trans from polezero subtype "file name.pz" to none
>
>
>
> ?? b) SAC> trans to polezero subtype "wood anderson file name.pz"
>
>
>
> ?? c) SAC> trans to wa
>
>
>
> ?? d) SAC> trans from polezero subtype "sation's file name.pz" to wa
>
>
>
> ?? e) SAC> trans from polezero subtype "sation's file name.pz" to wa to none
>
>
>
> ?? f) SAC> trans from evalresp fname RESP.SATION to wa
>
>
>
> ?? g) SAC> SAC> trans from polezero subtype "sation's file name.pz" freq 0.005 0.01 1.0 2.0
>
>
>
> 2. What the different utilizing of Response File and Polezero File?
>
> ?? I think polezero already included in responfile, is it right ?
>
>
>
> May you help me? Thank You very much
>
>
>
>
>
> Sincerely Yours
>
> Ami
>
> -------------- next part --------------
>
> An HTML attachment was scrubbed...
>
> URL:
>
>
>
> ------------------------------
>
>
>
> Message: 3
>
> Date: Sun, 17 Nov 2013 07:43:55 -0500 (EST)
>
> From: Arthur Snoke
>
> Subject: Re: [SAC-HELP] Remove Response Instrument
>
> To: amik Amik
>
> Cc: "sac-help at iris.washington.edu"
>
> Message-ID:
>
> Content-Type: text/plain; charset="iso-8859-1"; Format="flowed"
>
>
>
> I think the best way for you to understand what the various options do is
>
> to try them andsave the results. The TRANSFER help file at
>
> has answers
>
> to your explicit quesitons. If anything is not clear, let me know.
>
>
>
> On Sun, 17 Nov 2013, amik Amik wrote:
>
>
>
> > I am working on a local magnitude research. I want to remove response
>
> > instrument
>
> > from the data and simulate the response of Wood Anderson seismograph. What
>
> > should I do?
>
> > I have a few questions :
>
> > 1. Which one the true procedure and command in SAC :
>
> > ?? a) SAC> trans from evalresp to none
>
> > ?? ? ?and then
>
> > ?? ? ?SAC> trans from polezero subtype "file name.pz" to none
>
> >
>
> > ?? b) SAC> trans to polezero subtype "wood anderson file name.pz"
>
> >
>
> > ?? c) SAC> trans to wa
>
> >
>
> > ?? d) SAC> trans from polezero subtype "sation's file name.pz" to wa
>
> >
>
> > ?? e) SAC> trans from polezero subtype "sation's file name.pz" to wa to none
>
> >
>
> > ?? f) SAC> trans from evalresp fname RESP.SATION to wa
>
> >
>
> > ?? g) SAC> SAC> trans from polezero subtype "sation's file name.pz" freq
>
> > 0.005 0.01 1.0 2.0
>
> >
>
> > 2. What the different utilizing of Response File and Polezero File?
>
> > ?? I think polezero already included in responfile, is it right ?
>
> >
>
> > May you help me? Thank You very much
>
> >
>
> >
>
> > Sincerely Yours
>
> > Ami
>
> >
>
> >
>
>
>
> ------------------------------
>
>
>
> Message: 4
>
> Date: Sun, 17 Nov 2013 14:29:15 +0100
>
> From: "Milton P. Plasencia Linares"
>
> Subject: Re: [SAC-HELP] Remove Response Instrument
>
> To: "amik Amik"
>
> Cc: "sac-help at iris.washington.edu"
>
> Message-ID:
>
> Content-Type: text/plain;charset=ISO-8859-1;DelSp="Yes";
>
> format="flowed"
>
>
>
> look below,
>
>
>
> **********************************
>
> Milton P. PLASENCIA LINARES
>
>
>
> Dipartimento Centro di Ricerche Sismologiche
>
> Istituto Nazionale di Oceanografia e di Geofisica Sperimentale - OGS
>
>
>
> Borgo Grotta Gigante 42/C
>
> (34010) Sgonico - TRIESTE - ITALIA
>
> Tel: +39-040-2140 256/141
>
> Fax: +39-040-327307
>
>
>
> E-mail: mplasencia at inogs.it
>
>
>
> ASAIN (Antarctic Seismographic Argentinean Italian Network)
>
> *********************************
>
>
>
>
>
> Quoting "amik Amik" :
>
>
>
> > I am working on a local magnitude research. I want to remove
>
> > response instrument
>
> > from the data and simulate the response of Wood Anderson
>
> > seismograph. What should I do?
>
> > I have a few questions :
>
> > 1. Which one the true procedure and command in SAC :
>
> > ?? a) SAC> trans from evalresp to none
>
> > ?? ? ?and then
>
> > ?? ? ?SAC> trans from polezero subtype "file name.pz" to none
>
> >
>
> > ?? b) SAC> trans to polezero subtype "wood anderson file name.pz"
>
> >
>
> > ?? c) SAC> trans to wa
>
> >
>
> > ?? d) SAC> trans from polezero subtype "sation's file name.pz" to wa
>
> Option d) This is fine if you use the polezero station file.
>
> >
>
> > ?? e) SAC> trans from polezero subtype "sation's file name.pz" to wa to none
>
> >
>
> > ?? f) SAC> trans from evalresp fname RESP.SATION to wa
>
> >
>
> > ?? g) SAC> SAC> trans from polezero subtype "sation's file name.pz"
>
> > freq 0.005 0.01 1.0 2.0
>
> >
>
> > 2. What the different utilizing of Response File and Polezero File?
>
> Response file include the filter (FIR) coefficients
>
>
>
> > ?? I think polezero already included in responfile, is it right ?
>
> Yes.
>
> >
>
> > May you help me? Thank You very much
>
>
>
> My suggest ius use:
>
>
>
> > transfer from polezero subtype "PZ file" to wa freq 0.005 0.01 1.0 2.0
>
>
>
> >
>
> >
>
> > Sincerely Yours
>
> > Ami
>
> >
>
> Cheers,
>
>
>
> Milton
>
>
>
>
>
>
>
> ----------------------------------------------------------------
>
> This message was sent using IMP, the Internet Messaging Program.
>
>
>
>
>
>
>
>
>
> ------------------------------
>
>
>
> Message: 5
>
> Date: Mon, 18 Nov 2013 08:01:33 -0500
>
> From: Fiona Darbyshire
>
> Subject: [SAC-HELP] Calculation of AZ and BAZ in SAC
>
> To: sac-help at iris.washington.edu
>
> Message-ID:
>
>
>
> Content-Type: text/plain; charset=ISO-8859-1
>
>
>
> Hello,
>
>
>
> Could someone tell me a bit more about how AZ and BAZ are calculated in SAC?
>
>
>
> Up to now, e.g. when binning receiver functions, I have used BAZ and
>
> GCARC to group them together, and that's always seemed to work, so
>
> I've always assumed that the BAZ/GCARC (or DIST, I imagine) pair gives
>
> you a unique position from the point of interest (the station).
>
>
>
> This time, I have some data output that is expressed in AZ and DIST. I
>
> assumed (perhaps naively?) that this would also allow successful
>
> spatial grouping, but it turns out not to be the case; one can have
>
> the same forward azimuth for several different locations.
>
>
>
> Here's the example where I found the issue:
>
> Station lat, lon: 82.5033, -62.35 (ALE)
>
>
>
> Event1: lat 80.205, lon -1.091
>
> Event 2: lat 86.876, lon 54.373
>
> The two events are almost 1000km apart.
>
>
>
> Event 1: AZ 313, BAZ 72, GCARC 9, DIST 1006
>
> Event 2: AZ 314, BAZ 17, GCARC 9, DIST 1042
>
>
>
> I'd like to know more about the calculation, in particular because (i)
>
> I'd like to reassure myself that BAZ/distance does indeed give a
>
> unique location, and (ii) I don't understand how AZ is calculated. One
>
> website I looked at (Matlab) talks about rhumb lines vs great-circles;
>
> is that the issue? Will an AZ/distance pair always be non-unique?
>
> (Also most websites define back-azimuth as simply 180 opposite to
>
> azimuth, but I guess they aren't talking about spherical geometry
>
> then...)
>
>
>
> Thanks for any insight.
>
>
>
> Fiona Darbyshire.
>
>
>
> Centre de recherche GEOTOP, Universit? du Qu?bec ? Montr?al
>
>
>
>
>
>
>
> ------------------------------
>
>
>
> Message: 6
>
> Date: Mon, 18 Nov 2013 11:38:44 -0500
>
> From: Brian Savage
>
> Subject: Re: [SAC-HELP] Calculation of AZ and BAZ in SAC
>
> To: SAC HELP
>
> Message-ID:
>
> Content-Type: text/plain; charset="windows-1252"
>
>
>
> Fiona,
>
>
>
> The implementation of the computation of Great Circle Distance (degrees), Azimuth, Back Azimuth, and Distance (km) is based off of Rudoe's formula found in Geodesy by R.Bomford (1980). It assumes a Radius of 6378.160 km and a flattening of 1/298.2466081. I can send you the appropriate pages from R. Bomford (1980) if you would like.
>
>
>
> The azimuth and back-azimuth will generally not be offset by180 degrees, and some pairs of point will have "odd-looking" (not event close to 180 degrees) azimuth/back azimuth pairs.
>
>
>
> Note: There are more robust methods of calculating these quantities and the current implementation in SAC as well as many other implementations, up until recently [1], have trouble with particular pairs of points. For over ~ 99% of point pairs SAC's implementation produces the correct result, but that last 1% can be incorrect (sometimes badly).
>
>
>
> I hope this helps.
>
>
>
> Brian Savage
>
>
>
> [1] Karney, C. F. F. (2013). "Algorithms for geodesics". Journal of Geodesy 87 (1): 43?42. arXiv:1109.4448. Bibcode:2013JGeod..87...43K. doi:10.1007/s00190-012-0578-z (open access). Addenda.
>
>
>
>
>
> On Nov 18, 2013, at 8:01 AM, Fiona Darbyshire wrote:
>
>
>
> > Hello,
>
> >
>
> > Could someone tell me a bit more about how AZ and BAZ are calculated in SAC?
>
> >
>
> > Up to now, e.g. when binning receiver functions, I have used BAZ and
>
> > GCARC to group them together, and that's always seemed to work, so
>
> > I've always assumed that the BAZ/GCARC (or DIST, I imagine) pair gives
>
> > you a unique position from the point of interest (the station).
>
> >
>
> > This time, I have some data output that is expressed in AZ and DIST. I
>
> > assumed (perhaps naively?) that this would also allow successful
>
> > spatial grouping, but it turns out not to be the case; one can have
>
> > the same forward azimuth for several different locations.
>
> >
>
> > Here's the example where I found the issue:
>
> > Station lat, lon: 82.5033, -62.35 (ALE)
>
> >
>
> > Event1: lat 80.205, lon -1.091
>
> > Event 2: lat 86.876, lon 54.373
>
> > The two events are almost 1000km apart.
>
> >
>
> > Event 1: AZ 313, BAZ 72, GCARC 9, DIST 1006
>
> > Event 2: AZ 314, BAZ 17, GCARC 9, DIST 1042
>
> >
>
> > I'd like to know more about the calculation, in particular because (i)
>
> > I'd like to reassure myself that BAZ/distance does indeed give a
>
> > unique location, and (ii) I don't understand how AZ is calculated. One
>
> > website I looked at (Matlab) talks about rhumb lines vs great-circles;
>
> > is that the issue? Will an AZ/distance pair always be non-unique?
>
> > (Also most websites define back-azimuth as simply 180 opposite to
>
> > azimuth, but I guess they aren't talking about spherical geometry
>
> > then...)
>
> >
>
> > Thanks for any insight.
>
> >
>
> > Fiona Darbyshire.
>
> >
>
> > Centre de recherche GEOTOP, Universit? du Qu?bec ? Montr?al
>
> >
>
> > _______________________________________________
>
> > sac-help mailing list
>
> > sac-help at iris.washington.edu
>
> > http://www.iris.washington.edu/mailman/listinfo/sac-help
>
>
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